• Pattern Printing

    11:50 3
    Print this pattern. you can use any language to print this. and you are not allowed to use any predefined functions in order to print this.

    The complexity should be low. 
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    3 comments:

    1. Yash5 November 2017 at 13:48

      https://ideone.com/I3EVIs

      def printSpaces(n):
      for i in range(n):
      print(" ",end=" ")

      def printSqNum(k,n):
      for i in range(k,k+n):
      print(i**2,end=" ")

      k = 1
      n = 5

      for i in range(n):
      printSpaces(n-i-1)
      printSqNum(k,2*i+1)
      k = k + (2*i+1)
      print("\n")

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    2. Unknown5 November 2017 at 14:55

      //This program is in C
      #include

      int main()
      {
      int i,j,k,n,value=1;
      printf("Enter the no. of rows: ");
      scanf("%d",&n);
      for(i=1;i<=n;i++)
      {
      for(j=1;j<=n-i;j++)
      {
      printf(" ");
      }
      for(k=1;k<=2*i-1;k++)
      {
      printf("%d ",value*value);
      value++;
      }
      printf("\n");
      }

      return 0;
      }

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